In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy with?

In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole. With what minimum speed must the athlete leave the ground in order to lift his center of mass 2.25 m and cross the bar with a speed of 0.71 m/s?|||conservation of energy:





energy at position 2 = energy at position 1





position 2 = 2.25 m above position 1





1/2mgh + 1/2 mv2^2 = 1/2mv1^2


gh + v2^2 = v1^2





v2 = 0.71 m/s


h = 2.25 m


g = 9.8m/s^2





solve for v1